2025 ABSA 4th Class Power Engineer Part A Practice Test – Complete Prep

Question: 1 / 765

A mass of 600 kg is moved a horizontal distance of 40 m due to a force of 400 N. The amount of work done is:

16,000 J

To determine the amount of work done when a force is applied to move an object, the formula used is:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

In this scenario, the force applied is 400 N, and the object is moved a horizontal distance of 40 m. Since the force is applied in the direction of the movement, the angle \(\theta\) between the force and the direction of motion is 0 degrees. The cosine of 0 degrees is equal to 1, thus simplifying the equation to:

\[ \text{Work} = \text{Force} \times \text{Distance} \]

Substituting in the given values:

\[ \text{Work} = 400 \, \text{N} \times 40 \, \text{m} = 16,000 \, \text{J} \]

This calculation shows that the correct amount of work done is 16,000 Joules.

The other choices either misrepresent the calculation by introducing incorrect conversions or by using different units. For example, 24,000 J results from a misunderstanding of the force and distance

Get further explanation with Examzify DeepDiveBeta

24,000 J

24,000 kJ

1,600 MJ

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