What is the quantity of heat required to raise the temperature of 6.3 kg of glass from 6 degrees C to 210 degrees C if the specific heat capacity of glass is 670 J/kg K?

What is the quantity of heat required to raise the temperature of 6.3 kg of glass from 6 degrees C to 210 degrees C if the specific heat capacity of glass is 670 J/kg K?

• A. 886.4 kJ
• B. 861.2 kJ
• C. 25.3 kJ
• D. 911.7 kJ

Answer: (B)

To determine the quantity of heat required to raise the temperature of a substance, the formula used is: \[ Q = m \cdot c \cdot \Delta T \] where: - \( Q \) is the heat energy (in joules), - \( m \) is the mass of the substance (in kilograms), - \( c \) is the specific heat capacity (in J/kg·K), and - \( \Delta T \) is the change in temperature (in K or °C, since the size of the degree is the same). In this case, we have the mass of the glass as 6.3 kg, the specific heat capacity of glass as 670 J/kg·K, and the temperature change can be calculated as follows: \[ \Delta T = T_{final} - T_{initial} = 210°C - 6°C = 204°C \] Now, substituting these values into the heat energy formula gives: \[ Q = 6.3\, \text{kg} \cdot 670\, \text{J/kg·K} \cdot 204\, \text{K} \] Calculating this step-by-step: 1

To determine the quantity of heat required to raise the temperature of a substance, the formula used is:

[ Q = m \cdot c \cdot \Delta T ]

where:

• ( Q ) is the heat energy (in joules),

• ( m ) is the mass of the substance (in kilograms),

• ( c ) is the specific heat capacity (in J/kg·K), and

• ( \Delta T ) is the change in temperature (in K or °C, since the size of the degree is the same).

In this case, we have the mass of the glass as 6.3 kg, the specific heat capacity of glass as 670 J/kg·K, and the temperature change can be calculated as follows:

[

\Delta T = T_{final} - T_{initial} = 210°C - 6°C = 204°C

]

Now, substituting these values into the heat energy formula gives:

[

Q = 6.3, \text{kg} \cdot 670, \text{J/kg·K} \cdot 204, \text{K}

]

Calculating this step-by-step:

1